How to solve 63 - 5x + 1 = 0

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 63 - 5x + 1 = 0 | Equatix

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$$63-5x+1=0$$

$x = \frac{64}{5} = 12\frac{4}{5} = 12.8$

Add $63$ and $1$ to get $64$.

$$64-5x=0$$

Subtract $64$ from both sides. Anything subtracted from zero gives its negation.

$$-5x=-64$$

Divide both sides by $-5$.

$$x=\frac{-64}{-5}$$

Fraction $\frac{-64}{-5}$ can be simplified to $\frac{64}{5}$ by removing the negative sign from both the numerator and the denominator.

$$x=\frac{64}{5}$$