How to solve 6303 imes75

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 6303\times75 | Equatix

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Question

$$6303 \times 75$$

Evaluate

$472725$

Steps For Long Multiplication

First line up the numbers vertically and match the places from the right like this.

$$\begin{array}{c}\phantom{\times99}6303\\\underline{\times\phantom{9999}75}\\\end{array}$$

Now multiply the first number with the $1^{st}$ digit in $2^{nd}$ number to get intermediate results. That is Multiply 6303 with 5. Write the result 31515 at the end leaving 0 spaces to the right like this.

$$\begin{array}{c}\phantom{\times99}6303\\\underline{\times\phantom{9999}75}\\\phantom{\times9}31515\\\end{array}$$

Now multiply the first number with the $2^{nd}$ digit in $2^{nd}$ number to get intermediate results. That is Multiply 6303 with 7. Write the result 44121 at the end leaving 1 spaces to the right like this.

$$\begin{array}{c}\phantom{\times99}6303\\\underline{\times\phantom{9999}75}\\\phantom{\times9}31515\\\underline{\phantom{\times}44121\phantom{9}}\\\end{array}$$

Now add the intermediate results to get final answer.

$$\begin{array}{c}\phantom{\times99}6303\\\underline{\times\phantom{9999}75}\\\phantom{\times9}31515\\\underline{\phantom{\times}44121\phantom{9}}\\\phantom{\times}472725\end{array}$$

Show Solution

Factor

$3^{2}\times 5^{2}\times 11\times 191$