1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 6357 | Equatix - Math Solver

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Question

$$6357 \times \quad 25$$

Evaluate

$158925$

Steps For Long Multiplication

First line up the numbers vertically and match the places from the right like this.

$$\begin{array}{c}\phantom{\times99}6357\\\underline{\times\phantom{9999}25}\\\end{array}$$

Now multiply the first number with the $1^{st}$ digit in $2^{nd}$ number to get intermediate results. That is Multiply 6357 with 5. Write the result 31785 at the end leaving 0 spaces to the right like this.

$$\begin{array}{c}\phantom{\times99}6357\\\underline{\times\phantom{9999}25}\\\phantom{\times9}31785\\\end{array}$$

Now multiply the first number with the $2^{nd}$ digit in $2^{nd}$ number to get intermediate results. That is Multiply 6357 with 2. Write the result 12714 at the end leaving 1 spaces to the right like this.

$$\begin{array}{c}\phantom{\times99}6357\\\underline{\times\phantom{9999}25}\\\phantom{\times9}31785\\\underline{\phantom{\times}12714\phantom{9}}\\\end{array}$$

Now add the intermediate results to get final answer.

$$\begin{array}{c}\phantom{\times99}6357\\\underline{\times\phantom{9999}25}\\\phantom{\times9}31785\\\underline{\phantom{\times}12714\phantom{9}}\\\phantom{\times}158925\end{array}$$

Show Solution

Factor

$3\times 5^{2}\times 13\times 163$