Solve 64\div8\times5-3+5=21 | Equatix - Math Solver

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Example

3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$64 \div 8 \times 5-3+5=21$$

Verify

$\text{false}$

Solution Steps

Divide $64$ by $8$ to get $8$.

$$8\times 5-3+5=21$$

Multiply $8$ and $5$ to get $40$.

$$40-3+5=21$$

Subtract $3$ from $40$ to get $37$.

$$37+5=21$$

Add $37$ and $5$ to get $42$.

$$42=21$$

Compare $42$ and $21$.

$$\text{false}$$