$$64-3(13+2\times12\div8-3\times3)+11$$
$54$
$$64-3\left(13+\frac{24}{8}-3\times 3\right)+11$$
$$64-3\left(13+3-3\times 3\right)+11$$
$$64-3\left(16-3\times 3\right)+11$$
$$64-3\left(16-9\right)+11$$
$$64-3\times 7+11$$
$$64-21+11$$
$$43+11$$
$$54$$
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$2\times 3^{3}$