How to solve 645 imes321

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 645\times321 | Equatix

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Question

$$645 \times 321$$

Evaluate

$207045$

Steps For Long Multiplication

First line up the numbers vertically and match the places from the right like this.

$$\begin{array}{c}\phantom{\times999}645\\\underline{\times\phantom{999}321}\\\end{array}$$

Now multiply the first number with the $1^{st}$ digit in $2^{nd}$ number to get intermediate results. That is Multiply 645 with 1. Write the result 645 at the end leaving 0 spaces to the right like this.

$$\begin{array}{c}\phantom{\times999}645\\\underline{\times\phantom{999}321}\\\phantom{\times999}645\\\end{array}$$

Now multiply the first number with the $2^{nd}$ digit in $2^{nd}$ number to get intermediate results. That is Multiply 645 with 2. Write the result 1290 at the end leaving 1 spaces to the right like this.

$$\begin{array}{c}\phantom{\times999}645\\\underline{\times\phantom{999}321}\\\phantom{\times999}645\\\phantom{\times9}1290\phantom{9}\\\end{array}$$

Now multiply the first number with the $3^{rd}$ digit in $2^{nd}$ number to get intermediate results. That is Multiply 645 with 3. Write the result 1935 at the end leaving 2 spaces to the right like this.

$$\begin{array}{c}\phantom{\times999}645\\\underline{\times\phantom{999}321}\\\phantom{\times999}645\\\phantom{\times9}1290\phantom{9}\\\underline{\phantom{\times}1935\phantom{99}}\\\end{array}$$

Now add the intermediate results to get final answer.

$$\begin{array}{c}\phantom{\times999}645\\\underline{\times\phantom{999}321}\\\phantom{\times999}645\\\phantom{\times9}1290\phantom{9}\\\underline{\phantom{\times}1935\phantom{99}}\\\phantom{\times}207045\end{array}$$

Show Solution

Factor

$3^{2}\times 5\times 43\times 107$