How to solve 64m6-(27)^(18)

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 64m6-(27)^(18) | Equatix

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Question

$$64m6- { 27 }^{ 18 }$$

Differentiate w.r.t. m_6

$64$

Steps Using Derivative Rule for Sum

Calculate $27$ to the power of $18$ and get $58149737003040059690390169$.

$$\frac{\mathrm{d}}{\mathrm{d}m_{6}}(64m_{6}-58149737003040059690390169)$$

The derivative of a polynomial is the sum of the derivatives of its terms. The derivative of a constant term is $0$. The derivative of $ax^{n}$ is $nax^{n-1}$.

$$64m_{6}^{1-1}$$

Subtract $1$ from $1$.

$$64m_{6}^{0}$$

For any term $t$ except $0$, $t^{0}=1$.

$$64\times 1$$

For any term $t$, $t\times 1=t$ and $1t=t$.

$$64$$

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Evaluate

$64m_{6}-58149737003040059690390169$

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Example

Question

Differentiate w.r.t. m_6

Steps Using Derivative Rule for Sum

Evaluate

Solution Steps