How to solve 65 imes345434

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 65\times345434 | Equatix

Question

$$65 \times 345434$$

Evaluate

$22453210$

Steps For Long Multiplication

First line up the numbers vertically and match the places from the right like this.

$$\begin{array}{c}\phantom{\times999999}65\\\underline{\times\phantom{99}345434}\\\end{array}$$

Now multiply the first number with the $1^{st}$ digit in $2^{nd}$ number to get intermediate results. That is Multiply 65 with 4. Write the result 260 at the end leaving 0 spaces to the right like this.

$$\begin{array}{c}\phantom{\times999999}65\\\underline{\times\phantom{99}345434}\\\phantom{\times99999}260\\\end{array}$$

Now multiply the first number with the $2^{nd}$ digit in $2^{nd}$ number to get intermediate results. That is Multiply 65 with 3. Write the result 195 at the end leaving 1 spaces to the right like this.

$$\begin{array}{c}\phantom{\times999999}65\\\underline{\times\phantom{99}345434}\\\phantom{\times99999}260\\\phantom{\times9999}195\phantom{9}\\\end{array}$$

Now multiply the first number with the $3^{rd}$ digit in $2^{nd}$ number to get intermediate results. That is Multiply 65 with 4. Write the result 260 at the end leaving 2 spaces to the right like this.

$$\begin{array}{c}\phantom{\times999999}65\\\underline{\times\phantom{99}345434}\\\phantom{\times99999}260\\\phantom{\times9999}195\phantom{9}\\\phantom{\times999}260\phantom{99}\\\end{array}$$

Now multiply the first number with the $4^{th}$ digit in $2^{nd}$ number to get intermediate results. That is Multiply 65 with 5. Write the result 325 at the end leaving 3 spaces to the right like this.

Now multiply the first number with the $5^{th}$ digit in $2^{nd}$ number to get intermediate results. That is Multiply 65 with 4. Write the result 260 at the end leaving 4 spaces to the right like this.

$$\begin{array}{c}\phantom{\times999999}65\\\underline{\times\phantom{99}345434}\\\phantom{\times99999}260\\\phantom{\times9999}195\phantom{9}\\\phantom{\times999}260\phantom{99}\\\phantom{\times99}325\phantom{999}\\\phantom{\times9}260\phantom{9999}\\\end{array}$$

Now multiply the first number with the $6^{th}$ digit in $2^{nd}$ number to get intermediate results. That is Multiply 65 with 3. Write the result 195 at the end leaving 5 spaces to the right like this.

Now add the intermediate results to get final answer.

Show Solution

Factor

$2\times 5\times 13\times 172717$

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Steps For Long Multiplication

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