Solve 66\div[(-2)\times(-5)+4-3]+88\div[(-2-5-3)\times(-4)]

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Question

$$66 \div [(-2) \times (-5)+4-3]+88 \div [(-2-5-3) \times (-4)]$$

Evaluate

$\frac{41}{5}=8.2$

Solution Steps

Multiply $-2$ and $-5$ to get $10$.

$$\frac{66}{10+4-3}+\frac{88}{\left(-2-5-3\right)\left(-4\right)}$$

Add $10$ and $4$ to get $14$.

$$\frac{66}{14-3}+\frac{88}{\left(-2-5-3\right)\left(-4\right)}$$

Subtract $3$ from $14$ to get $11$.

$$\frac{66}{11}+\frac{88}{\left(-2-5-3\right)\left(-4\right)}$$

Divide $66$ by $11$ to get $6$.

$$6+\frac{88}{\left(-2-5-3\right)\left(-4\right)}$$

Subtract $5$ from $-2$ to get $-7$.

$$6+\frac{88}{\left(-7-3\right)\left(-4\right)}$$

Subtract $3$ from $-7$ to get $-10$.

$$6+\frac{88}{-10\left(-4\right)}$$

Multiply $-10$ and $-4$ to get $40$.

$$6+\frac{88}{40}$$

Reduce the fraction $\frac{88}{40}$ to lowest terms by extracting and canceling out $8$.

$$6+\frac{11}{5}$$

Convert $6$ to fraction $\frac{30}{5}$.

$$\frac{30}{5}+\frac{11}{5}$$

Since $\frac{30}{5}$ and $\frac{11}{5}$ have the same denominator, add them by adding their numerators.

$$\frac{30+11}{5}$$

Add $30$ and $11$ to get $41$.

$$\frac{41}{5}$$

Show Solution

Factor

$\frac{41}{5} = 8\frac{1}{5} = 8.2$