1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 6615/21 | Equatix

Basic Math

Pre-Algebra

Algebra

Trigonometry

Calculus

Precalculus

Statistics

Finite Math

Linear Algebra

Chemistry

Question

$$6615\div21$$

Evaluate

$315$

Steps For Long Division Method

Use the $1^{st}$ digit $6$ from dividend $6615$

$$\begin{array}{l}\phantom{21)}\phantom{1}\\21\overline{)6615}\\\end{array}$$

Since $6$ is less than $21$, use the next digit $6$ from dividend $6615$ and add $0$ to the quotient

$$\begin{array}{l}\phantom{21)}0\phantom{2}\\21\overline{)6615}\\\end{array}$$

Use the $2^{nd}$ digit $6$ from dividend $6615$

$$\begin{array}{l}\phantom{21)}0\phantom{3}\\21\overline{)6615}\\\end{array}$$

Find closest multiple of $21$ to $66$. We see that $3 \times 21 = 63$ is the nearest. Now subtract $63$ from $66$ to get reminder $3$. Add $3$ to quotient.

$$\begin{array}{l}\phantom{21)}03\phantom{4}\\21\overline{)6615}\\\phantom{21)}\underline{\phantom{}63\phantom{99}}\\\phantom{21)9}3\\\end{array}$$

Use the $3^{rd}$ digit $1$ from dividend $6615$

$$\begin{array}{l}\phantom{21)}03\phantom{5}\\21\overline{)6615}\\\phantom{21)}\underline{\phantom{}63\phantom{99}}\\\phantom{21)9}31\\\end{array}$$

Find closest multiple of $21$ to $31$. We see that $1 \times 21 = 21$ is the nearest. Now subtract $21$ from $31$ to get reminder $10$. Add $1$ to quotient.

$$\begin{array}{l}\phantom{21)}031\phantom{6}\\21\overline{)6615}\\\phantom{21)}\underline{\phantom{}63\phantom{99}}\\\phantom{21)9}31\\\phantom{21)}\underline{\phantom{9}21\phantom{9}}\\\phantom{21)9}10\\\end{array}$$

Use the $4^{th}$ digit $5$ from dividend $6615$

$$\begin{array}{l}\phantom{21)}031\phantom{7}\\21\overline{)6615}\\\phantom{21)}\underline{\phantom{}63\phantom{99}}\\\phantom{21)9}31\\\phantom{21)}\underline{\phantom{9}21\phantom{9}}\\\phantom{21)9}105\\\end{array}$$

Find closest multiple of $21$ to $105$. We see that $5 \times 21 = 105$ is the nearest. Now subtract $105$ from $105$ to get reminder $0$. Add $5$ to quotient.

$$\begin{array}{l}\phantom{21)}0315\phantom{8}\\21\overline{)6615}\\\phantom{21)}\underline{\phantom{}63\phantom{99}}\\\phantom{21)9}31\\\phantom{21)}\underline{\phantom{9}21\phantom{9}}\\\phantom{21)9}105\\\phantom{21)}\underline{\phantom{9}105\phantom{}}\\\phantom{21)9999}0\\\end{array}$$

Since $0$ is less than $21$, stop the division. The reminder is $0$. The topmost line $0315$ is the quotient. Remove all zeros at the start of the quotient to get the actual quotient $315$.

$$\text{Quotient: }315$$ $$\text{Reminder: }0$$

Show Solution

Factor

$3^{2}\times 5\times 7$