Solve 67theta + 235 + 814 = | Equatix - Math Solver

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Example

3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$67\theta+235+814=$$

Differentiate w.r.t. θ

$67$

Steps Using Derivative Rule for Sum

Add $235$ and $814$ to get $1049$.

$$\frac{\mathrm{d}}{\mathrm{d}\theta }(67\theta +1049)$$

The derivative of a polynomial is the sum of the derivatives of its terms. The derivative of a constant term is $0$. The derivative of $ax^{n}$ is $nax^{n-1}$.

$$67\theta ^{1-1}$$

Subtract $1$ from $1$.

$$67\theta ^{0}$$

For any term $t$ except $0$, $t^{0}=1$.

$$67\times 1$$

For any term $t$, $t\times 1=t$ and $1t=t$.

$$67$$

Evaluate

$67\theta +1049$