How to solve 687648 imes475

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 687648\times475 | Equatix

Basic Math

Pre-Algebra

Algebra

Trigonometry

Calculus

Precalculus

Statistics

Finite Math

Linear Algebra

Chemistry

Question

$$687648 \times 475$$

Evaluate

$326632800$

Steps For Long Multiplication

First line up the numbers vertically and match the places from the right like this.

$$\begin{array}{c}\phantom{\times999}687648\\\underline{\times\phantom{999999}475}\\\end{array}$$

Now multiply the first number with the $1^{st}$ digit in $2^{nd}$ number to get intermediate results. That is Multiply 687648 with 5. Write the result 3438240 at the end leaving 0 spaces to the right like this.

$$\begin{array}{c}\phantom{\times999}687648\\\underline{\times\phantom{999999}475}\\\phantom{\times99}3438240\\\end{array}$$

Now multiply the first number with the $2^{nd}$ digit in $2^{nd}$ number to get intermediate results. That is Multiply 687648 with 7. Write the result 4813536 at the end leaving 1 spaces to the right like this.

$$\begin{array}{c}\phantom{\times999}687648\\\underline{\times\phantom{999999}475}\\\phantom{\times99}3438240\\\phantom{\times9}4813536\phantom{9}\\\end{array}$$

Now multiply the first number with the $3^{rd}$ digit in $2^{nd}$ number to get intermediate results. That is Multiply 687648 with 4. Write the result 2750592 at the end leaving 2 spaces to the right like this.

$$\begin{array}{c}\phantom{\times999}687648\\\underline{\times\phantom{999999}475}\\\phantom{\times99}3438240\\\phantom{\times9}4813536\phantom{9}\\\underline{\phantom{\times}2750592\phantom{99}}\\\end{array}$$

Now add the intermediate results to get final answer.

Show Solution

Factor

$2^{5}\times 3\times 5^{2}\times 13\times 19^{2}\times 29$