How to solve 6a+8b+4a-8b

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 6a+8b+4a-8b | Equatix

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Example

3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$6a+8b+4a-8b$$

Evaluate

$10a$

Show Solution

Differentiate w.r.t. a

$10$

Steps Using Definition of a Derivative

Combine $6a$ and $4a$ to get $10a$.

$$\frac{\mathrm{d}}{\mathrm{d}a}(10a+8b-8b)$$

Combine $8b$ and $-8b$ to get $0$.

$$\frac{\mathrm{d}}{\mathrm{d}a}(10a)$$

The derivative of $ax^{n}$ is $nax^{n-1}$.

$$10a^{1-1}$$

Subtract $1$ from $1$.

$$10a^{0}$$

For any term $t$ except $0$, $t^{0}=1$.

$$10\times 1$$

For any term $t$, $t\times 1=t$ and $1t=t$.

$$10$$

Show Solution

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Example

Question

Evaluate

Solution Steps

Differentiate w.r.t. a

Steps Using Definition of a Derivative