How to solve 6t + 3t + 9t =

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 6t + 3t + 9t = | Equatix

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3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$6t+3t+9t=$$

Evaluate

$18t$

Show Solution

Differentiate w.r.t. t

$18$

Steps Using Definition of a Derivative

Combine $6t$ and $3t$ to get $9t$.

$$\frac{\mathrm{d}}{\mathrm{d}t}(9t+9t)$$

Combine $9t$ and $9t$ to get $18t$.

$$\frac{\mathrm{d}}{\mathrm{d}t}(18t)$$

The derivative of $ax^{n}$ is $nax^{n-1}$.

$$18t^{1-1}$$

Subtract $1$ from $1$.

$$18t^{0}$$

For any term $t$ except $0$, $t^{0}=1$.

$$18\times 1$$

For any term $t$, $t\times 1=t$ and $1t=t$.

$$18$$

Show Solution

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Example

Question

Evaluate

Solution Steps

Differentiate w.r.t. t

Steps Using Definition of a Derivative