How to solve 6x-4+-3x+2+4x-2

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 6x-4+-3x+2+4x-2 | Equatix

Basic Math

Pre-Algebra

Algebra

Trigonometry

Calculus

Precalculus

Statistics

Finite Math

Linear Algebra

Chemistry

Question

$$6x-4+-3x+2+4x-2$$

Evaluate

$7x-4$

Solution Steps

Combine $6x$ and $-3x$ to get $3x$.

$$3x-4+2+4x-2$$

Add $-4$ and $2$ to get $-2$.

$$3x-2+4x-2$$

Combine $3x$ and $4x$ to get $7x$.

$$7x-2-2$$

Subtract $2$ from $-2$ to get $-4$.

$$7x-4$$

Show Solution

Differentiate w.r.t. x

$7$

Steps Using Derivative Rule for Sum

Combine $6x$ and $-3x$ to get $3x$.

$$\frac{\mathrm{d}}{\mathrm{d}x}(3x-4+2+4x-2)$$

Add $-4$ and $2$ to get $-2$.

$$\frac{\mathrm{d}}{\mathrm{d}x}(3x-2+4x-2)$$

Combine $3x$ and $4x$ to get $7x$.

$$\frac{\mathrm{d}}{\mathrm{d}x}(7x-2-2)$$

Subtract $2$ from $-2$ to get $-4$.

$$\frac{\mathrm{d}}{\mathrm{d}x}(7x-4)$$

The derivative of a polynomial is the sum of the derivatives of its terms. The derivative of a constant term is $0$. The derivative of $ax^{n}$ is $nax^{n-1}$.

$$7x^{1-1}$$

Subtract $1$ from $1$.

$$7x^{0}$$

For any term $t$ except $0$, $t^{0}=1$.

$$7\times 1$$

For any term $t$, $t\times 1=t$ and $1t=t$.

$$7$$