Question

$$6x+\frac{2}{x}=1$$

Answer

x=(1+sqrt(47)*IM)/12,(1-sqrt(47)*IM)/12

Solution


Multiply both sides by \(x\).
\[6{x}^{2}+2=x\]
Move all terms to one side.
\[6{x}^{2}+2-x=0\]
Use the Quadratic Formula.
\[x=\frac{1+\sqrt{47}\imath }{12},\frac{1-\sqrt{47}\imath }{12}\]