How to solve 6y+24+2=4y+58

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 6y+24+2=4y+58 | Equatix

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Question

$$6y+24+2=4y+58$$

Solve for y

$y=16$

Steps for Solving Linear Equation

Add $24$ and $2$ to get $26$.

$$6y+26=4y+58$$

Subtract $4y$ from both sides.

$$6y+26-4y=58$$

Combine $6y$ and $-4y$ to get $2y$.

$$2y+26=58$$

Subtract $26$ from both sides.

$$2y=58-26$$

Subtract $26$ from $58$ to get $32$.

$$2y=32$$

Divide both sides by $2$.

$$y=\frac{32}{2}$$

Divide $32$ by $2$ to get $16$.

$$y=16$$

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Question

Solve for y

Steps for Solving Linear Equation