Solve 6z+10=-2 | Equatix - Math Solver

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Example

3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$6z+10=-2$$

Solve for z

$z=-2$

Steps for Solving Linear Equation

Subtract $10$ from both sides.

$$6z=-2-10$$

Subtract $10$ from $-2$ to get $-12$.

$$6z=-12$$

Divide both sides by $6$.

$$z=\frac{-12}{6}$$

Divide $-12$ by $6$ to get $-2$.

$$z=-2$$