Solve 6z + 10 = - 8 | Equatix - Math Solver

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Example

3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$6z+10=-8$$

Solve for z

$z=-3$

Steps for Solving Linear Equation

Subtract $10$ from both sides.

$$6z=-8-10$$

Subtract $10$ from $-8$ to get $-18$.

$$6z=-18$$

Divide both sides by $6$.

$$z=\frac{-18}{6}$$

Divide $-18$ by $6$ to get $-3$.

$$z=-3$$