How to solve 7/10+4/5

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 7/10+4/5 | Equatix

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$$7/10+4/5$$

$\frac{3}{2}=1.5$

Least common multiple of $10$ and $5$ is $10$. Convert $\frac{7}{10}$ and $\frac{4}{5}$ to fractions with denominator $10$.

$$\frac{7}{10}+\frac{8}{10}$$

Since $\frac{7}{10}$ and $\frac{8}{10}$ have the same denominator, add them by adding their numerators.

$$\frac{7+8}{10}$$

Add $7$ and $8$ to get $15$.

$$\frac{15}{10}$$

Reduce the fraction $\frac{15}{10}$ to lowest terms by extracting and canceling out $5$.

$$\frac{3}{2}$$

$\frac{3}{2} = 1\frac{1}{2} = 1.5$