1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 7/1|1|5 | Equatix

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Question

$$7/1|1|5$$

Evaluate

$35$

Solution Steps

Anything divided by one gives itself.

$$7|1|\times 5$$

The absolute value of a real number $a$ is $a$ when $a\geq 0$, or $-a$ when $a<0$. The absolute value of $1$ is $1$.

$$7\times 1\times 5$$

Multiply $7$ and $1$ to get $7$.

$$7\times 5$$

Multiply $7$ and $5$ to get $35$.

$$35$$

Show Solution

Factor

$5\times 7$

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