1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 7/2-2/3 | Equatix

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Question

$$7/2-2/3$$

$\frac{17}{6}\approx 2.833333333$

Least common multiple of $2$ and $3$ is $6$. Convert $\frac{7}{2}$ and $\frac{2}{3}$ to fractions with denominator $6$.

$$\frac{21}{6}-\frac{4}{6}$$

Since $\frac{21}{6}$ and $\frac{4}{6}$ have the same denominator, subtract them by subtracting their numerators.

$$\frac{21-4}{6}$$

Subtract $4$ from $21$ to get $17$.

$$\frac{17}{6}$$

$\frac{17}{2 \cdot 3} = 2\frac{5}{6} = 2.8333333333333335$