1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 7/2+4 | Equatix

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3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$7/2+4$$

Evaluate

$\frac{15}{2}=7.5$

Solution Steps

Convert $4$ to fraction $\frac{8}{2}$.

$$\frac{7}{2}+\frac{8}{2}$$

Since $\frac{7}{2}$ and $\frac{8}{2}$ have the same denominator, add them by adding their numerators.

$$\frac{7+8}{2}$$

Add $7$ and $8$ to get $15$.

$$\frac{15}{2}$$

Show Solution

Factor

$\frac{3 \cdot 5}{2} = 7\frac{1}{2} = 7.5$

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