Solve 7/2x-5/2x=20/3x+10 | Equatix - Math Solver

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Example

3(r+2s)=2t-4

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3(r+2s)=2t-4

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Question

$$7/2x-5/2x=20/3x+10$$

Solve for x

$x = -\frac{30}{17} = -1\frac{13}{17} \approx -1.764705882$

Steps for Solving Linear Equation

Combine $\frac{7}{2}x$ and $-\frac{5}{2}x$ to get $x$.

$$x=\frac{20}{3}x+10$$

Subtract $\frac{20}{3}x$ from both sides.

$$x-\frac{20}{3}x=10$$

Combine $x$ and $-\frac{20}{3}x$ to get $-\frac{17}{3}x$.

$$-\frac{17}{3}x=10$$

Multiply both sides by $-\frac{3}{17}$, the reciprocal of $-\frac{17}{3}$.

$$x=10\left(-\frac{3}{17}\right)$$

Express $10\left(-\frac{3}{17}\right)$ as a single fraction.

$$x=\frac{10\left(-3\right)}{17}$$

Multiply $10$ and $-3$ to get $-30$.

$$x=\frac{-30}{17}$$

Fraction $\frac{-30}{17}$ can be rewritten as $-\frac{30}{17}$ by extracting the negative sign.

$$x=-\frac{30}{17}$$