$$7/5 \times (-2/3) \times (-4/7)$$
$\frac{8}{15}\approx 0.533333333$
$$\frac{7}{5}\left(-\frac{2}{3}\right)\times \frac{-4}{7}$$
$$\frac{7\left(-2\right)}{5\times 3}\times \frac{-4}{7}$$
$$\frac{-14}{15}\times \frac{-4}{7}$$
$$-\frac{14}{15}\times \frac{-4}{7}$$
$$-\frac{14}{15}\left(-\frac{4}{7}\right)$$
$$\frac{-14\left(-4\right)}{15\times 7}$$
$$\frac{56}{105}$$
$$\frac{8}{15}$$
Show Solution
Hide Solution
$\frac{2 ^ {3}}{3 \cdot 5} = 0.5333333333333333$