1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 7/9/5/7 | Equatix

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Question

$$7/9/5/7$$

$\frac{1}{45}\approx 0.022222222$

Express $\frac{\frac{\frac{7}{9}}{5}}{7}$ as a single fraction.

$$\frac{\frac{7}{9}}{5\times 7}$$

Multiply $5$ and $7$ to get $35$.

$$\frac{\frac{7}{9}}{35}$$

Express $\frac{\frac{7}{9}}{35}$ as a single fraction.

$$\frac{7}{9\times 35}$$

Multiply $9$ and $35$ to get $315$.

$$\frac{7}{315}$$

Reduce the fraction $\frac{7}{315}$ to lowest terms by extracting and canceling out $7$.

$$\frac{1}{45}$$

$\frac{1}{3 ^ {2} \cdot 5} = 0.022222222222222223$