How to solve 7/9+6/8+6/3

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 7/9+6/8+6/3 | Equatix

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Question

$$7/9+6/8+6/3$$

Evaluate

$\frac{127}{36}\approx 3.527777778$

Solution Steps

Reduce the fraction $\frac{6}{8}$ to lowest terms by extracting and canceling out $2$.

$$\frac{7}{9}+\frac{3}{4}+\frac{6}{3}$$

Least common multiple of $9$ and $4$ is $36$. Convert $\frac{7}{9}$ and $\frac{3}{4}$ to fractions with denominator $36$.

$$\frac{28}{36}+\frac{27}{36}+\frac{6}{3}$$

Since $\frac{28}{36}$ and $\frac{27}{36}$ have the same denominator, add them by adding their numerators.

$$\frac{28+27}{36}+\frac{6}{3}$$

Add $28$ and $27$ to get $55$.

$$\frac{55}{36}+\frac{6}{3}$$

Divide $6$ by $3$ to get $2$.

$$\frac{55}{36}+2$$

Convert $2$ to fraction $\frac{72}{36}$.

$$\frac{55}{36}+\frac{72}{36}$$

Since $\frac{55}{36}$ and $\frac{72}{36}$ have the same denominator, add them by adding their numerators.

$$\frac{55+72}{36}$$

Add $55$ and $72$ to get $127$.

$$\frac{127}{36}$$

Show Solution

Factor

$\frac{127}{2 ^ {2} \cdot 3 ^ {2}} = 3\frac{19}{36} = 3.5277777777777777$