How to solve 7/(20OF3-5+6)+9

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 7/(20OF3-5+6)+9 | Equatix

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$$7/(20OF3-5+6)+9$$

$\frac{4\left(45F_{3}O+4\right)}{20F_{3}O+1}$

Add $-5$ and $6$ to get $1$.

$$\frac{7}{20OF_{3}+1}+9$$

To add or subtract expressions, expand them to make their denominators the same. Multiply $9$ times $\frac{20OF_{3}+1}{20OF_{3}+1}$.

$$\frac{7}{20OF_{3}+1}+\frac{9\left(20OF_{3}+1\right)}{20OF_{3}+1}$$

Since $\frac{7}{20OF_{3}+1}$ and $\frac{9\left(20OF_{3}+1\right)}{20OF_{3}+1}$ have the same denominator, add them by adding their numerators.

$$\frac{7+9\left(20OF_{3}+1\right)}{20OF_{3}+1}$$

Do the multiplications in $7+9\left(20OF_{3}+1\right)$.

$$\frac{7+180OF_{3}+9}{20OF_{3}+1}$$

Combine like terms in $7+180OF_{3}+9$.

$$\frac{16+180OF_{3}}{20OF_{3}+1}$$

$-\frac{140O}{\left(20F_{3}O+1\right)^{2}}$