How to solve 7 2/12 - 3/41

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 7 2/12 - 3/41 | Equatix

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$$7\frac{2}{12}-\frac{3}{41}$$

$\frac{1745}{246}\approx 7.093495935$

Multiply $7$ and $12$ to get $84$.

$$\frac{84+2}{12}-\frac{3}{41}$$

Add $84$ and $2$ to get $86$.

$$\frac{86}{12}-\frac{3}{41}$$

Reduce the fraction $\frac{86}{12}$ to lowest terms by extracting and canceling out $2$.

$$\frac{43}{6}-\frac{3}{41}$$

Least common multiple of $6$ and $41$ is $246$. Convert $\frac{43}{6}$ and $\frac{3}{41}$ to fractions with denominator $246$.

$$\frac{1763}{246}-\frac{18}{246}$$

Since $\frac{1763}{246}$ and $\frac{18}{246}$ have the same denominator, subtract them by subtracting their numerators.

$$\frac{1763-18}{246}$$

Subtract $18$ from $1763$ to get $1745$.

$$\frac{1745}{246}$$

$\frac{5 \cdot 349}{2 \cdot 3 \cdot 41} = 7\frac{23}{246} = 7.09349593495935$