How to solve 7 3/4 - 2/13

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 7 3/4 - 2/13 | Equatix

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$$7\frac{3}{4}-\frac{2}{13}$$

$\frac{395}{52}\approx 7.596153846$

Multiply $7$ and $4$ to get $28$.

$$\frac{28+3}{4}-\frac{2}{13}$$

Add $28$ and $3$ to get $31$.

$$\frac{31}{4}-\frac{2}{13}$$

Least common multiple of $4$ and $13$ is $52$. Convert $\frac{31}{4}$ and $\frac{2}{13}$ to fractions with denominator $52$.

$$\frac{403}{52}-\frac{8}{52}$$

Since $\frac{403}{52}$ and $\frac{8}{52}$ have the same denominator, subtract them by subtracting their numerators.

$$\frac{403-8}{52}$$

Subtract $8$ from $403$ to get $395$.

$$\frac{395}{52}$$

$\frac{5 \cdot 79}{2 ^ {2} \cdot 13} = 7\frac{31}{52} = 7.596153846153846$