Solve 7(3)/(5)\div2(4)/(5) | Equatix

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Question

$$7 \frac{ 3 }{ 5 } \div 2 \frac{ 4 }{ 5 }$$

$\frac{19}{7}\approx 2.714285714$

Divide $\frac{7\times 5+3}{5}$ by $\frac{2\times 5+4}{5}$ by multiplying $\frac{7\times 5+3}{5}$ by the reciprocal of $\frac{2\times 5+4}{5}$.

$$\frac{\left(7\times 5+3\right)\times 5}{5\left(2\times 5+4\right)}$$

Cancel out $5$ in both numerator and denominator.

$$\frac{3+5\times 7}{4+2\times 5}$$

Multiply $5$ and $7$ to get $35$.

$$\frac{3+35}{4+2\times 5}$$

Add $3$ and $35$ to get $38$.

$$\frac{38}{4+2\times 5}$$

Multiply $2$ and $5$ to get $10$.

$$\frac{38}{4+10}$$

Add $4$ and $10$ to get $14$.

$$\frac{38}{14}$$

Reduce the fraction $\frac{38}{14}$ to lowest terms by extracting and canceling out $2$.

$$\frac{19}{7}$$

$\frac{19}{7} = 2\frac{5}{7} = 2.7142857142857144$