1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve + (-4 ) | Equatix

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3(r+2s)=2t-4

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Question

$$7 - 8 \div ( - 2 ) + 3 \times ( - 4 )$$

Evaluate

$-1$

Solution Steps

Divide $8$ by $-2$ to get $-4$.

$$7-\left(-4\right)+3\left(-4\right)$$

The opposite of $-4$ is $4$.

$$7+4+3\left(-4\right)$$

Add $7$ and $4$ to get $11$.

$$11+3\left(-4\right)$$

Multiply $3$ and $-4$ to get $-12$.

$$11-12$$

Subtract $12$ from $11$ to get $-1$.

$$-1$$

Show Solution

Factor

$-1$

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