Solve [7 - \{2 ^ 3 - 7\}](2 - 2) | Equatix - Math Solver

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Example

3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$[7-\{2^{3}-7\}]\cdot(2-2)$$

Evaluate

$0$

Solution Steps

Calculate $2$ to the power of $3$ and get $8$.

$$\left(7-\left(8-7\right)\right)\left(2-2\right)$$

Subtract $7$ from $8$ to get $1$.

$$\left(7-1\right)\left(2-2\right)$$

Subtract $1$ from $7$ to get $6$.

$$6\left(2-2\right)$$

Subtract $2$ from $2$ to get $0$.

$$6\times 0$$

Multiply $6$ and $0$ to get $0$.

$$0$$

Factor

$0$