How to solve 7(2x+4)-8(3x+4)

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 7(2x+4)-8(3x+4) | Equatix

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3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$7(2x+4)-8(3x+4)$$

Evaluate

$-10x-4$

Solution Steps

Use the distributive property to multiply $7$ by $2x+4$.

$$14x+28-8\left(3x+4\right)$$

Use the distributive property to multiply $-8$ by $3x+4$.

$$14x+28-24x-32$$

Combine $14x$ and $-24x$ to get $-10x$.

$$-10x+28-32$$

Subtract $32$ from $28$ to get $-4$.

$$-10x-4$$

Show Solution

Expand

$-10x-4$

Solution Steps

Use the distributive property to multiply $7$ by $2x+4$.

$$14x+28-8\left(3x+4\right)$$

Use the distributive property to multiply $-8$ by $3x+4$.

$$14x+28-24x-32$$

Combine $14x$ and $-24x$ to get $-10x$.

$$-10x+28-32$$

Subtract $32$ from $28$ to get $-4$.

$$-10x-4$$

Show Solution

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Question

Evaluate

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Solution Steps