$$7(2y-4)+5(3y-4)+2(2y+4)=22$$
$y = \frac{62}{33} = 1\frac{29}{33} \approx 1.878787879$
$$14y-28+5\left(3y-4\right)+2\left(2y+4\right)=22$$
$$14y-28+15y-20+2\left(2y+4\right)=22$$
$$29y-28-20+2\left(2y+4\right)=22$$
$$29y-48+2\left(2y+4\right)=22$$
$$29y-48+4y+8=22$$
$$33y-48+8=22$$
$$33y-40=22$$
$$33y=22+40$$
$$33y=62$$
$$y=\frac{62}{33}$$
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