How to solve 7(4-3x)=2(8x-9)+6

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 7(4-3x)=2(8x-9)+6 | Equatix

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Question

$$7(4-3x)=2(8x-9)+6$$

Solve for x

$x = \frac{40}{37} = 1\frac{3}{37} \approx 1.081081081$

Steps for Solving Linear Equation

Use the distributive property to multiply $7$ by $4-3x$.

$$28-21x=2\left(8x-9\right)+6$$

Use the distributive property to multiply $2$ by $8x-9$.

$$28-21x=16x-18+6$$

Add $-18$ and $6$ to get $-12$.

$$28-21x=16x-12$$

Subtract $16x$ from both sides.

$$28-21x-16x=-12$$

Combine $-21x$ and $-16x$ to get $-37x$.

$$28-37x=-12$$

Subtract $28$ from both sides.

$$-37x=-12-28$$

Subtract $28$ from $-12$ to get $-40$.

$$-37x=-40$$

Divide both sides by $-37$.

$$x=\frac{-40}{-37}$$

Fraction $\frac{-40}{-37}$ can be simplified to $\frac{40}{37}$ by removing the negative sign from both the numerator and the denominator.

$$x=\frac{40}{37}$$

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