Solve 7(x-3)-10=2(3x-5)-3(-7x | Equatix - Math Solver

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Example

3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$7(x-3)-10=2(3x-5)-3(-7x$$

Solve for x

$x = -\frac{21}{20} = -1\frac{1}{20} = -1.05$

Steps for Solving Linear Equation

Use the distributive property to multiply $7$ by $x-3$.

$$7x-21-10=2\left(3x-5\right)-3\left(-7\right)x$$

Subtract $10$ from $-21$ to get $-31$.

$$7x-31=2\left(3x-5\right)-3\left(-7\right)x$$

Use the distributive property to multiply $2$ by $3x-5$.

$$7x-31=6x-10-3\left(-7\right)x$$

Multiply $3$ and $-7$ to get $-21$.

$$7x-31=6x-10-\left(-21x\right)$$

The opposite of $-21x$ is $21x$.

$$7x-31=6x-10+21x$$

Combine $6x$ and $21x$ to get $27x$.

$$7x-31=27x-10$$

Subtract $27x$ from both sides.

$$7x-31-27x=-10$$

Combine $7x$ and $-27x$ to get $-20x$.

$$-20x-31=-10$$

Add $31$ to both sides.

$$-20x=-10+31$$

Add $-10$ and $31$ to get $21$.

$$-20x=21$$

Divide both sides by $-20$.

$$x=\frac{21}{-20}$$

Fraction $\frac{21}{-20}$ can be rewritten as $-\frac{21}{20}$ by extracting the negative sign.

$$x=-\frac{21}{20}$$