$$7(x-3)-10=2(3x-5)-3(-7x+4$$
$x=-\frac{9}{20}=-0.45$
$$7x-21-10=2\left(3x-5\right)-3\left(-7x+4\right)$$
$$7x-31=2\left(3x-5\right)-3\left(-7x+4\right)$$
$$7x-31=6x-10-3\left(-7x+4\right)$$
$$7x-31=6x-10+21x-12$$
$$7x-31=27x-10-12$$
$$7x-31=27x-22$$
$$7x-31-27x=-22$$
$$-20x-31=-22$$
$$-20x=-22+31$$
$$-20x=9$$
$$x=\frac{9}{-20}$$
$$x=-\frac{9}{20}$$
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