How to solve 7(y-2)-5(y-3)

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 7(y-2)-5(y-3) | Equatix

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a⋅(b-2)=3b

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a⋅(b-2)=3b

Question

$$7(y-2)-5(y-3)$$

Evaluate

$2y+1$

Solution Steps

Use the distributive property to multiply $7$ by $y-2$.

$$7y-14-5\left(y-3\right)$$

Use the distributive property to multiply $-5$ by $y-3$.

$$7y-14-5y+15$$

Combine $7y$ and $-5y$ to get $2y$.

$$2y-14+15$$

Add $-14$ and $15$ to get $1$.

$$2y+1$$

Show Solution

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$2y+1$

Solution Steps

Use the distributive property to multiply $7$ by $y-2$.

$$7y-14-5\left(y-3\right)$$

Use the distributive property to multiply $-5$ by $y-3$.

$$7y-14-5y+15$$

Combine $7y$ and $-5y$ to get $2y$.

$$2y-14+15$$

Add $-14$ and $15$ to get $1$.

$$2y+1$$

Show Solution

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Solution Steps