Solve 7 + 23 - 8 + 48 - 2 - 58 | Equatix - Math Solver

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Example

3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$7+23-8+48-2-58$$

Evaluate

$10$

Solution Steps

Add $7$ and $23$ to get $30$.

$$30-8+48-2-58$$

Subtract $8$ from $30$ to get $22$.

$$22+48-2-58$$

Add $22$ and $48$ to get $70$.

$$70-2-58$$

Subtract $2$ from $70$ to get $68$.

$$68-58$$

Subtract $58$ from $68$ to get $10$.

$$10$$

Factor

$2\times 5$