1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 7+3/5 | Equatix

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3(r+2s)=2t-4

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Question

$$7+3/5$$

Evaluate

$\frac{38}{5}=7.6$

Solution Steps

Convert $7$ to fraction $\frac{35}{5}$.

$$\frac{35}{5}+\frac{3}{5}$$

Since $\frac{35}{5}$ and $\frac{3}{5}$ have the same denominator, add them by adding their numerators.

$$\frac{35+3}{5}$$

Add $35$ and $3$ to get $38$.

$$\frac{38}{5}$$

Show Solution

Factor

$\frac{2 \cdot 19}{5} = 7\frac{3}{5} = 7.6$

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