Question

$$7^{(n+1)}+(n^{2}+-1)}; 7^{(n^{2}-n)}+(2n+2)}$$

Answer

$$7^(n+1)+n^2-1;7^(n^2-n)+2*n+2$$

Solution


Simplify  \({n}^{2}+-1\)  to  \({n}^{2}-1\).
\[\begin{aligned}&{7}^{n+1}+{n}^{2}-1\\&{7}^{{n}^{2}-n}+2n+2\end{aligned}\]