Solve 7\times(2x-3)+8=14x-21+8= | Equatix - Math Solver

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Example

3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$7 \times (2x-3)+8=14x-21+8=$$

Solve for x (complex solution)

$x\in \mathrm{C}$

Solution Steps

Use the distributive property to multiply $7$ by $2x-3$.

$$14x-21+8=14x-21+8$$

Add $-21$ and $8$ to get $-13$.

$$14x-13=14x-21+8$$

Add $-21$ and $8$ to get $-13$.

$$14x-13=14x-13$$

Subtract $14x$ from both sides.

$$14x-13-14x=-13$$

Combine $14x$ and $-14x$ to get $0$.

$$-13=-13$$

Compare $-13$ and $-13$.

$$\text{true}$$

This is true for any $x$.

$$x\in \mathrm{C}$$

Solve for x

$x\in \mathrm{R}$

Solution Steps

Use the distributive property to multiply $7$ by $2x-3$.

$$14x-21+8=14x-21+8$$

Add $-21$ and $8$ to get $-13$.

$$14x-13=14x-21+8$$

Add $-21$ and $8$ to get $-13$.

$$14x-13=14x-13$$

Subtract $14x$ from both sides.

$$14x-13-14x=-13$$

Combine $14x$ and $-14x$ to get $0$.

$$-13=-13$$

Compare $-13$ and $-13$.

$$\text{true}$$

This is true for any $x$.

$$x\in \mathrm{R}$$