How to solve 764897 imes252

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 764897\times252 | Equatix

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Question

$$764897 \times 252$$

Evaluate

$192754044$

Steps For Long Multiplication

First line up the numbers vertically and match the places from the right like this.

$$\begin{array}{c}\phantom{\times999}764897\\\underline{\times\phantom{999999}252}\\\end{array}$$

Now multiply the first number with the $1^{st}$ digit in $2^{nd}$ number to get intermediate results. That is Multiply 764897 with 2. Write the result 1529794 at the end leaving 0 spaces to the right like this.

$$\begin{array}{c}\phantom{\times999}764897\\\underline{\times\phantom{999999}252}\\\phantom{\times99}1529794\\\end{array}$$

Now multiply the first number with the $2^{nd}$ digit in $2^{nd}$ number to get intermediate results. That is Multiply 764897 with 5. Write the result 3824485 at the end leaving 1 spaces to the right like this.

$$\begin{array}{c}\phantom{\times999}764897\\\underline{\times\phantom{999999}252}\\\phantom{\times99}1529794\\\phantom{\times9}3824485\phantom{9}\\\end{array}$$

Now multiply the first number with the $3^{rd}$ digit in $2^{nd}$ number to get intermediate results. That is Multiply 764897 with 2. Write the result 1529794 at the end leaving 2 spaces to the right like this.

$$\begin{array}{c}\phantom{\times999}764897\\\underline{\times\phantom{999999}252}\\\phantom{\times99}1529794\\\phantom{\times9}3824485\phantom{9}\\\underline{\phantom{\times}1529794\phantom{99}}\\\end{array}$$

Now add the intermediate results to get final answer.

Show Solution

Factor

$2^{2}\times 3^{2}\times 7^{2}\times 113\times 967$