How to solve 7689 imes628

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 7689\times628 | Equatix

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Question

$$7689 \times 628$$

Evaluate

$4828692$

Steps For Long Multiplication

First line up the numbers vertically and match the places from the right like this.

$$\begin{array}{c}\phantom{\times999}7689\\\underline{\times\phantom{9999}628}\\\end{array}$$

Now multiply the first number with the $1^{st}$ digit in $2^{nd}$ number to get intermediate results. That is Multiply 7689 with 8. Write the result 61512 at the end leaving 0 spaces to the right like this.

$$\begin{array}{c}\phantom{\times999}7689\\\underline{\times\phantom{9999}628}\\\phantom{\times99}61512\\\end{array}$$

Now multiply the first number with the $2^{nd}$ digit in $2^{nd}$ number to get intermediate results. That is Multiply 7689 with 2. Write the result 15378 at the end leaving 1 spaces to the right like this.

$$\begin{array}{c}\phantom{\times999}7689\\\underline{\times\phantom{9999}628}\\\phantom{\times99}61512\\\phantom{\times9}15378\phantom{9}\\\end{array}$$

Now multiply the first number with the $3^{rd}$ digit in $2^{nd}$ number to get intermediate results. That is Multiply 7689 with 6. Write the result 46134 at the end leaving 2 spaces to the right like this.

$$\begin{array}{c}\phantom{\times999}7689\\\underline{\times\phantom{9999}628}\\\phantom{\times99}61512\\\phantom{\times9}15378\phantom{9}\\\underline{\phantom{\times}46134\phantom{99}}\\\end{array}$$

Now add the intermediate results to get final answer.

Show Solution

Factor

$2^{2}\times 3\times 11\times 157\times 233$