How to solve 7a + 8b = 9c + 8b

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 7a + 8b = 9c + 8b | Equatix

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Example

3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$7a+8b=9c+8b$$

Solve for a

$a=\frac{9c}{7}$

Steps for Solving Linear Equation

Subtract $8b$ from both sides.

$$7a=9c+8b-8b$$

Combine $8b$ and $-8b$ to get $0$.

$$7a=9c$$

Divide both sides by $7$.

$$\frac{7a}{7}=\frac{9c}{7}$$

Dividing by $7$ undoes the multiplication by $7$.

$$a=\frac{9c}{7}$$

Show Solution

Solve for b

$b\in \mathrm{R}$
$a=\frac{9c}{7}$

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Example

Question

Solve for a

Steps for Solving Linear Equation

Solve for b