How to solve 7x-3+2x+6-5x-4

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 7x-3+2x+6-5x-4 | Equatix

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Question

$$7x-3+2x+6-5x-4$$

Evaluate

$4x-1$

Solution Steps

Combine $7x$ and $2x$ to get $9x$.

$$9x-3+6-5x-4$$

Add $-3$ and $6$ to get $3$.

$$9x+3-5x-4$$

Combine $9x$ and $-5x$ to get $4x$.

$$4x+3-4$$

Subtract $4$ from $3$ to get $-1$.

$$4x-1$$

Show Solution

Differentiate w.r.t. x

$4$

Steps Using Derivative Rule for Sum

Combine $7x$ and $2x$ to get $9x$.

$$\frac{\mathrm{d}}{\mathrm{d}x}(9x-3+6-5x-4)$$

Add $-3$ and $6$ to get $3$.

$$\frac{\mathrm{d}}{\mathrm{d}x}(9x+3-5x-4)$$

Combine $9x$ and $-5x$ to get $4x$.

$$\frac{\mathrm{d}}{\mathrm{d}x}(4x+3-4)$$

Subtract $4$ from $3$ to get $-1$.

$$\frac{\mathrm{d}}{\mathrm{d}x}(4x-1)$$

The derivative of a polynomial is the sum of the derivatives of its terms. The derivative of a constant term is $0$. The derivative of $ax^{n}$ is $nax^{n-1}$.

$$4x^{1-1}$$

Subtract $1$ from $1$.

$$4x^{0}$$

For any term $t$ except $0$, $t^{0}=1$.

$$4\times 1$$

For any term $t$, $t\times 1=t$ and $1t=t$.

$$4$$