Question

$$7x+5y=32; x+7y=56$$

Answer

x=-14/11;y=90/11

Solution


Solve for \(x\) in \(x+7y=56\).
\[x=56-7y\]
Substitute \(x=56-7y\) into \(7x+5y=32\).
\[392-44y=32\]
Solve for \(y\) in \(392-44y=32\).
\[y=\frac{90}{11}\]
Substitute \(y=\frac{90}{11}\) into \(x=56-7y\).
\[x=-\frac{14}{11}\]
Therefore,
\[\begin{aligned}&x=-\frac{14}{11}\\&y=\frac{90}{11}\end{aligned}\]