Solve 7x + 6x - 30 + 0 | Equatix - Math Solver

Fractions & Decimals

Ratios & Proportions

Basic Number Theory

Integers & Absolute Values

Factors & Multiples

Prime Factorization

Basic Equations & Inequalities

Coordinate Plane & Graphing

Linear Equations & Inequalities

Quadratic Equations

Polynomials & Factoring

Functions & Graphs

Systems of Equations

Trigonometric Functions

Trigonometric Identities & Equations

Right Triangle Trigonometry

Graphing Trigonometric Functions

Limits & Continuity

Derivatives & Applications

Integrals & Applications

Series & Sequences

Multivariable Calculus

Functions & Graphs

Polynomial & Rational Functions

Exponential & Logarithmic Functions

Sequences & Series

Descriptive Statistics

Normal Distribution

Hypothesis Testing

Regression Analysis

Linear Programming

Sets & Counting

Eigenvalues & Eigenvectors

Linear Transformations

Atomic Structure

Thermochemistry

Example

3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$7x+6x-30+0$$

Evaluate

$13x-30$

Differentiate w.r.t. x

$13$

Steps Using Derivative Rule for Sum

Combine $7x$ and $6x$ to get $13x$.

$$\frac{\mathrm{d}}{\mathrm{d}x}(13x-30+0)$$

Add $-30$ and $0$ to get $-30$.

$$\frac{\mathrm{d}}{\mathrm{d}x}(13x-30)$$

The derivative of a polynomial is the sum of the derivatives of its terms. The derivative of a constant term is $0$. The derivative of $ax^{n}$ is $nax^{n-1}$.

$$13x^{1-1}$$

Subtract $1$ from $1$.

$$13x^{0}$$

For any term $t$ except $0$, $t^{0}=1$.

$$13\times 1$$

For any term $t$, $t\times 1=t$ and $1t=t$.

$$13$$