How to solve 7x+7-2(x-3)=0

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 7x+7-2(x-3)=0 | Equatix

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$$7x+7-2(x-3)=0$$

$x = -\frac{13}{5} = -2\frac{3}{5} = -2.6$

Use the distributive property to multiply $-2$ by $x-3$.

$$7x+7-2x+6=0$$

Combine $7x$ and $-2x$ to get $5x$.

$$5x+7+6=0$$

Add $7$ and $6$ to get $13$.

$$5x+13=0$$

Subtract $13$ from both sides. Anything subtracted from zero gives its negation.

$$5x=-13$$

Divide both sides by $5$.

$$x=\frac{-13}{5}$$

Fraction $\frac{-13}{5}$ can be rewritten as $-\frac{13}{5}$ by extracting the negative sign.

$$x=-\frac{13}{5}$$